Write in Standard Form 2(4k^2-2k)-3(-6k^2+4)+2k(k-1)

$2 (4 k^{2} - 2 k) - 3 (- 6 k^{2} + 4) + 2 k (k - 1)$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Simplify each term.

Apply the distributive property.

$2 (4 k^{2}) + 2 (- 2 k) - 3 (- 6 k^{2} + 4) + 2 k (k - 1)$

Multiply $4$ by $2$ .

$8 k^{2} + 2 (- 2 k) - 3 (- 6 k^{2} + 4) + 2 k (k - 1)$

Multiply $- 2$ by $2$ .

$8 k^{2} - 4 k - 3 (- 6 k^{2} + 4) + 2 k (k - 1)$

Apply the distributive property.

$8 k^{2} - 4 k - 3 (- 6 k^{2}) - 3 \cdot 4 + 2 k (k - 1)$

Multiply $- 6$ by $- 3$ .

$8 k^{2} - 4 k + 18 k^{2} - 3 \cdot 4 + 2 k (k - 1)$

Multiply $- 3$ by $4$ .

$8 k^{2} - 4 k + 18 k^{2} - 12 + 2 k (k - 1)$

Add $8 k^{2}$ and $18 k^{2}$ .

$26 k^{2} - 4 k - 12 + 2 k (k - 1)$