Write in Standard Form 2-8x+2x^2=4-3x^2-3x

$2 - 8 x + 2 x^{2} = 4 - 3 x^{2} - 3 x$

Step 1

Move all the expressions to the left side of the equation.

Subtract $4$ from both sides of the equation.

$2 - 8 x + 2 x^{2} - 4 = - 3 x^{2} - 3 x$

Add $3 x^{2}$ to both sides of the equation.

$2 - 8 x + 2 x^{2} - 4 + 3 x^{2} = - 3 x$

Add $3 x$ to both sides of the equation.

$2 - 8 x + 2 x^{2} - 4 + 3 x^{2} + 3 x = 0$

Step 2

Simplify $2 - 8 x + 2 x^{2} - 4 + 3 x^{2} + 3 x$ .

Subtract $4$ from $2$ .

$- 8 x + 2 x^{2} - 2 + 3 x^{2} + 3 x = 0$

Add $- 8 x$ and $3 x$ .

$2 x^{2} - 2 + 3 x^{2} - 5 x = 0$

Add $2 x^{2}$ and $3 x^{2}$ .

$5 x^{2} - 2 - 5 x = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

Move $- 2$ .

$5 x^{2} - 5 x - 2 = 0$

Step 5