Write in Standard Form 2x^2+y^2-8=0

$2 x^{2} + y^{2} - 8 = 0$

Add $8$ to both sides of the equation.

$2 x^{2} + y^{2} = 8$

Divide each term by $8$ to make the right side equal to one.

$\frac{2 x^{2}}{8} + \frac{y^{2}}{8} = \frac{8}{8}$

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$\frac{x^{2}}{4} + \frac{y^{2}}{8} = 1$

Write in Standard Form 2x^2+y^2-8=0

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