Write in Standard Form (3x^3+4x^2)-(2x^3+3x^2-x)

$(3 x^{3} + 4 x^{2}) - (2 x^{3} + 3 x^{2} - x)$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Step 2

Simplify each term.

Apply the distributive property.

$3 x^{3} + 4 x^{2} - (2 x^{3}) - (3 x^{2}) - - x$

Simplify.

Multiply $2$ by $- 1$ .

$3 x^{3} + 4 x^{2} - 2 x^{3} - (3 x^{2}) - - x$

Multiply $3$ by $- 1$ .

$3 x^{3} + 4 x^{2} - 2 x^{3} - 3 x^{2} - - x$

Multiply $- - x$ .

Multiply $- 1$ by $- 1$ .

$3 x^{3} + 4 x^{2} - 2 x^{3} - 3 x^{2} + 1 x$

Multiply $x$ by $1$ .

$3 x^{3} + 4 x^{2} - 2 x^{3} - 3 x^{2} + x$

Step 3

Simplify by adding terms.

Subtract $2 x^{3}$ from $3 x^{3}$ .

$x^{3} + 4 x^{2} - 3 x^{2} + x$

Subtract $3 x^{2}$ from $4 x^{2}$ .

$x^{3} + x^{2} + x$