Write in Standard Form 3x+4y-5=12-x+5y

$3 x + 4 y - 5 = 12 - x + 5 y$

The standard form of a linear equation is $A x + B y = C$ .

Move all terms containing variables to the left side of the equation.

Add $x$ to both sides of the equation.

$3 x + 4 y - 5 + x = 12 + 5 y$

Subtract $5 y$ from both sides of the equation.

$3 x + 4 y - 5 + x - 5 y = 12$

Add $3 x$ and $x$ .

$4 x + 4 y - 5 - 5 y = 12$

Subtract $5 y$ from $4 y$ .

$4 x - y - 5 = 12$

Move all terms not containing a variable to the right side of the equation.

Add $5$ to both sides of the equation.

$4 x - y = 12 + 5$

Add $12$ and $5$ .

$4 x - y = 17$