Write in Standard Form 3x(x-2)=-7x+1

$3 x (x - 2) = - 7 x + 1$

Step 1

Move all the expressions to the left side of the equation.

Add $7 x$ to both sides of the equation.

$3 x (x - 2) + 7 x = 1$

Subtract $1$ from both sides of the equation.

$3 x (x - 2) + 7 x - 1 = 0$

Step 2

Simplify $3 x (x - 2) + 7 x - 1$ .

Simplify each term.

Apply the distributive property.

$3 x \cdot x + 3 x \cdot - 2 + 7 x - 1 = 0$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$3 (x \cdot x) + 3 x \cdot - 2 + 7 x - 1 = 0$

Multiply $x$ by $x$ .

$3 x^{2} + 3 x \cdot - 2 + 7 x - 1 = 0$

Multiply $- 2$ by $3$ .

$3 x^{2} - 6 x + 7 x - 1 = 0$

Add $- 6 x$ and $7 x$ .

$3 x^{2} + x - 1 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $3 x^{2} + x - 1$ .

$3 x^{2} + x - 1 = 0$

Step 5