Write in Standard Form 4(1+4x)=x(x-7)

$4 (1 + 4 x) = x (x - 7)$

Step 1

Subtract $x (x - 7)$ from both sides of the equation.

$4 (1 + 4 x) - x (x - 7) = 0$

Step 2

Simplify $4 (1 + 4 x) - x (x - 7)$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 1 + 4 (4 x) - x (x - 7) = 0$

Multiply $4$ by $1$ .

$4 + 4 (4 x) - x (x - 7) = 0$

Multiply $4$ by $4$ .

$4 + 16 x - x (x - 7) = 0$

Apply the distributive property.

$4 + 16 x - x \cdot x - x \cdot - 7 = 0$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$4 + 16 x - (x \cdot x) - x \cdot - 7 = 0$

Multiply $x$ by $x$ .

$4 + 16 x - x^{2} - x \cdot - 7 = 0$

Multiply $- 7$ by $- 1$ .

$4 + 16 x - x^{2} + 7 x = 0$

Add $16 x$ and $7 x$ .

$4 - x^{2} + 23 x = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

Move $4$ .

$- x^{2} + 23 x + 4 = 0$

Step 5