Write in Standard Form 4+ square root of -9

$4 + \sqrt{- 9}$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Step 2

Simplify each term.

Rewrite $- 9$ as $- 1 (9)$ .

$4 + \sqrt{- 1 (9)}$

Rewrite $\sqrt{- 1 (9)}$ as $\sqrt{- 1} \cdot \sqrt{9}$ .

$4 + \sqrt{- 1} \cdot \sqrt{9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$4 + i \cdot \sqrt{9}$

Rewrite $9$ as $3^{2}$ .

$4 + i \cdot \sqrt{3^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$4 + i \cdot 3$

Move $3$ to the left of $i$ .

$4 + 3 i$