Write in Standard Form 40=3(2)^x-5

$40 = 3 {(2)}^{x} - 5$

Step 1

Move all the expressions to the left side of the equation.

Subtract $3 {(2)}^{x}$ from both sides of the equation.

$40 - 3 {(2)}^{x} = - 5$

Add $5$ to both sides of the equation.

$40 - 3 {(2)}^{x} + 5 = 0$

Step 2

Add $40$ and $5$ .

$45 - 3 \cdot 2^{x} = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $45 - 3 \cdot 2^{x}$ .

$45 - 3 \cdot 2^{x} = 0$

Step 5