Write in Standard Form 6-12x=(x-6)^2

$6 - 12 x = {(x - 6)}^{2}$

Step 1

Subtract ${(x - 6)}^{2}$ from both sides of the equation.

$6 - 12 x - {(x - 6)}^{2} = 0$

Step 2

Simplify $6 - 12 x - {(x - 6)}^{2}$ .

Simplify each term.

Rewrite ${(x - 6)}^{2}$ as $(x - 6) (x - 6)$ .

$6 - 12 x - ((x - 6) (x - 6)) = 0$

Expand $(x - 6) (x - 6)$ using the FOIL Method.

Apply the distributive property.

$6 - 12 x - (x (x - 6) - 6 (x - 6)) = 0$

Apply the distributive property.

$6 - 12 x - (x \cdot x + x \cdot - 6 - 6 (x - 6)) = 0$

Apply the distributive property.

$6 - 12 x - (x \cdot x + x \cdot - 6 - 6 x - 6 \cdot - 6) = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$6 - 12 x - (x^{2} + x \cdot - 6 - 6 x - 6 \cdot - 6) = 0$

Move $- 6$ to the left of $x$ .

$6 - 12 x - (x^{2} - 6 \cdot x - 6 x - 6 \cdot - 6) = 0$

Multiply $- 6$ by $- 6$ .

$6 - 12 x - (x^{2} - 6 x - 6 x + 36) = 0$

Subtract $6 x$ from $- 6 x$ .

$6 - 12 x - (x^{2} - 12 x + 36) = 0$

Apply the distributive property.

$6 - 12 x - x^{2} - (- 12 x) - 1 \cdot 36 = 0$

Simplify.

Multiply $- 12$ by $- 1$ .

$6 - 12 x - x^{2} + 12 x - 1 \cdot 36 = 0$

Multiply $- 1$ by $36$ .

$6 - 12 x - x^{2} + 12 x - 36 = 0$

Combine the opposite terms in $6 - 12 x - x^{2} + 12 x - 36$ .

Add $- 12 x$ and $12 x$ .

$6 - x^{2} + 0 - 36 = 0$

Add $6 - x^{2}$ and $0$ .

$6 - x^{2} - 36 = 0$

Subtract $36$ from $6$ .

$- x^{2} - 30 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $- x^{2} - 30$ .

$- x^{2} - 30 = 0$

Step 5

Write in Standard Form 6-12x=(x-6)^2

Related Questions

Support LCMGCF.com by disabling your adblocker.