Write in Standard Form 6+3x^2=-8x+2x^2-5

$6 + 3 x^{2} = - 8 x + 2 x^{2} - 5$

Step 1

Move all the expressions to the left side of the equation.

Add $8 x$ to both sides of the equation.

$6 + 3 x^{2} + 8 x = 2 x^{2} - 5$

Subtract $2 x^{2}$ from both sides of the equation.

$6 + 3 x^{2} + 8 x - 2 x^{2} = - 5$

Add $5$ to both sides of the equation.

$6 + 3 x^{2} + 8 x - 2 x^{2} + 5 = 0$

Step 2

Simplify $6 + 3 x^{2} + 8 x - 2 x^{2} + 5$ .

Add $6$ and $5$ .

$3 x^{2} + 8 x - 2 x^{2} + 11 = 0$

Subtract $2 x^{2}$ from $3 x^{2}$ .

$x^{2} + 8 x + 11 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $x^{2} + 8 x + 11$ .

$x^{2} + 8 x + 11 = 0$

Step 5