Write in Standard Form 7x+8+2x^2=2x+1+x^2

$7 x + 8 + 2 x^{2} = 2 x + 1 + x^{2}$

Step 1

Move all the expressions to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$7 x + 8 + 2 x^{2} - 2 x = 1 + x^{2}$

Subtract $1$ from both sides of the equation.

$7 x + 8 + 2 x^{2} - 2 x - 1 = x^{2}$

Subtract $x^{2}$ from both sides of the equation.

$7 x + 8 + 2 x^{2} - 2 x - 1 - x^{2} = 0$

Step 2

Simplify $7 x + 8 + 2 x^{2} - 2 x - 1 - x^{2}$ .

Subtract $2 x$ from $7 x$ .

$5 x + 8 + 2 x^{2} - 1 - x^{2} = 0$

Subtract $1$ from $8$ .

$5 x + 2 x^{2} + 7 - x^{2} = 0$

Subtract $x^{2}$ from $2 x^{2}$ .

$5 x + x^{2} + 7 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

Reorder $5 x$ and $x^{2}$ .

$x^{2} + 5 x + 7 = 0$

Step 5