Write in Standard Form (8n-3n^4+10n^2)-(3n^2+11n^4-7)

$(8 n - 3 n^{4} + 10 n^{2}) - (3 n^{2} + 11 n^{4} - 7)$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Step 2

Simplify each term.

Apply the distributive property.

$8 n - 3 n^{4} + 10 n^{2} - (3 n^{2}) - (11 n^{4}) - - 7$

Simplify.

Multiply $3$ by $- 1$ .

$8 n - 3 n^{4} + 10 n^{2} - 3 n^{2} - (11 n^{4}) - - 7$

Multiply $11$ by $- 1$ .

$8 n - 3 n^{4} + 10 n^{2} - 3 n^{2} - 11 n^{4} - - 7$

Multiply $- 1$ by $- 7$ .

$8 n - 3 n^{4} + 10 n^{2} - 3 n^{2} - 11 n^{4} + 7$

Step 3

Simplify by adding terms.

Subtract $11 n^{4}$ from $- 3 n^{4}$ .

$8 n - 14 n^{4} + 10 n^{2} - 3 n^{2} + 7$

Subtract $3 n^{2}$ from $10 n^{2}$ .

$8 n - 14 n^{4} + 7 n^{2} + 7$

Move $8 n$ .

$- 14 n^{4} + 7 n^{2} + 8 n + 7$