Write in Standard Form (x+2)^2=3(x+2)

${(x + 2)}^{2} = 3 (x + 2)$

Step 1

Subtract $3 (x + 2)$ from both sides of the equation.

${(x + 2)}^{2} - 3 (x + 2) = 0$

Step 2

Simplify ${(x + 2)}^{2} - 3 (x + 2)$ .

Simplify each term.

Rewrite ${(x + 2)}^{2}$ as $(x + 2) (x + 2)$ .

$(x + 2) (x + 2) - 3 (x + 2) = 0$

Expand $(x + 2) (x + 2)$ using the FOIL Method.

Apply the distributive property.

$x (x + 2) + 2 (x + 2) - 3 (x + 2) = 0$

Apply the distributive property.

$x \cdot x + x \cdot 2 + 2 (x + 2) - 3 (x + 2) = 0$

Apply the distributive property.

$x \cdot x + x \cdot 2 + 2 x + 2 \cdot 2 - 3 (x + 2) = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 2 + 2 x + 2 \cdot 2 - 3 (x + 2) = 0$

Move $2$ to the left of $x$ .

$x^{2} + 2 \cdot x + 2 x + 2 \cdot 2 - 3 (x + 2) = 0$

Multiply $2$ by $2$ .

$x^{2} + 2 x + 2 x + 4 - 3 (x + 2) = 0$

Add $2 x$ and $2 x$ .

$x^{2} + 4 x + 4 - 3 (x + 2) = 0$

Apply the distributive property.

$x^{2} + 4 x + 4 - 3 x - 3 \cdot 2 = 0$

Multiply $- 3$ by $2$ .

$x^{2} + 4 x + 4 - 3 x - 6 = 0$

Subtract $3 x$ from $4 x$ .

$x^{2} + x + 4 - 6 = 0$

Subtract $6$ from $4$ .

$x^{2} + x - 2 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $x^{2} + x - 2$ .

$x^{2} + x - 2 = 0$

Step 5