Write in Standard Form (x^2)/2+(4x)/3=6

$\frac{x^{2}}{2} + \frac{4 x}{3} = 6$

Subtract $6$ from both sides of the equation.

$\frac{x^{2}}{2} + \frac{4 x}{3} - 6 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Reorder terms.

$\frac{1}{2} x^{2} + \frac{4}{3} x - 6 = 0$