Write in Standard Form ((x+2)^2)/5+((x-2)^2)/3=16/3

$\frac{{(x + 2)}^{2}}{5} + \frac{{(x - 2)}^{2}}{3} = \frac{16}{3}$

Step 1

Subtract $\frac{16}{3}$ from both sides of the equation.

$\frac{{(x + 2)}^{2}}{5} + \frac{{(x - 2)}^{2}}{3} - \frac{16}{3} = 0$

Step 2

Simplify $\frac{{(x + 2)}^{2}}{5} + \frac{{(x - 2)}^{2}}{3} - \frac{16}{3}$ .

To write $\frac{{(x + 2)}^{2}}{5}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{{(x + 2)}^{2}}{5} \cdot \frac{3}{3} + \frac{{(x - 2)}^{2}}{3} - \frac{16}{3} = 0$

To write $\frac{{(x - 2)}^{2}}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{{(x + 2)}^{2}}{5} \cdot \frac{3}{3} + \frac{{(x - 2)}^{2}}{3} \cdot \frac{5}{5} - \frac{16}{3} = 0$

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{{(x + 2)}^{2}}{5}$ by $\frac{3}{3}$ .

$\frac{{(x + 2)}^{2} \cdot 3}{5 \cdot 3} + \frac{{(x - 2)}^{2}}{3} \cdot \frac{5}{5} - \frac{16}{3} = 0$

Multiply $5$ by $3$ .

$\frac{{(x + 2)}^{2} \cdot 3}{15} + \frac{{(x - 2)}^{2}}{3} \cdot \frac{5}{5} - \frac{16}{3} = 0$

Multiply $\frac{{(x - 2)}^{2}}{3}$ by $\frac{5}{5}$ .

$\frac{{(x + 2)}^{2} \cdot 3}{15} + \frac{{(x - 2)}^{2} \cdot 5}{3 \cdot 5} - \frac{16}{3} = 0$

Multiply $3$ by $5$ .

$\frac{{(x + 2)}^{2} \cdot 3}{15} + \frac{{(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Combine the numerators over the common denominator.

$\frac{{(x + 2)}^{2} \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Simplify the numerator.

Rewrite ${(x + 2)}^{2}$ as $(x + 2) (x + 2)$ .

$\frac{(x + 2) (x + 2) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Expand $(x + 2) (x + 2)$ using the FOIL Method.

Apply the distributive property.

$\frac{(x (x + 2) + 2 (x + 2)) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Apply the distributive property.

$\frac{(x \cdot x + x \cdot 2 + 2 (x + 2)) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Apply the distributive property.

$\frac{(x \cdot x + x \cdot 2 + 2 x + 2 \cdot 2) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$\frac{(x^{2} + x \cdot 2 + 2 x + 2 \cdot 2) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Move $2$ to the left of $x$ .

$\frac{(x^{2} + 2 \cdot x + 2 x + 2 \cdot 2) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Multiply $2$ by $2$ .

$\frac{(x^{2} + 2 x + 2 x + 4) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Add $2 x$ and $2 x$ .

$\frac{(x^{2} + 4 x + 4) \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Apply the distributive property.

$\frac{x^{2} \cdot 3 + 4 x \cdot 3 + 4 \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Simplify.

Move $3$ to the left of $x^{2}$ .

$\frac{3 \cdot x^{2} + 4 x \cdot 3 + 4 \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Multiply $3$ by $4$ .

$\frac{3 \cdot x^{2} + 12 x + 4 \cdot 3 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Multiply $4$ by $3$ .

$\frac{3 \cdot x^{2} + 12 x + 12 + {(x - 2)}^{2} \cdot 5}{15} - \frac{16}{3} = 0$

Rewrite ${(x - 2)}^{2}$ as $(x - 2) (x - 2)$ .

$\frac{3 x^{2} + 12 x + 12 + (x - 2) (x - 2) \cdot 5}{15} - \frac{16}{3} = 0$

Expand $(x - 2) (x - 2)$ using the FOIL Method.

Apply the distributive property.

$\frac{3 x^{2} + 12 x + 12 + (x (x - 2) - 2 (x - 2)) \cdot 5}{15} - \frac{16}{3} = 0$

Apply the distributive property.

$\frac{3 x^{2} + 12 x + 12 + (x \cdot x + x \cdot - 2 - 2 (x - 2)) \cdot 5}{15} - \frac{16}{3} = 0$

Apply the distributive property.

$\frac{3 x^{2} + 12 x + 12 + (x \cdot x + x \cdot - 2 - 2 x - 2 \cdot - 2) \cdot 5}{15} - \frac{16}{3} = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$\frac{3 x^{2} + 12 x + 12 + (x^{2} + x \cdot - 2 - 2 x - 2 \cdot - 2) \cdot 5}{15} - \frac{16}{3} = 0$

Move $- 2$ to the left of $x$ .

$\frac{3 x^{2} + 12 x + 12 + (x^{2} - 2 \cdot x - 2 x - 2 \cdot - 2) \cdot 5}{15} - \frac{16}{3} = 0$

Multiply $- 2$ by $- 2$ .

$\frac{3 x^{2} + 12 x + 12 + (x^{2} - 2 x - 2 x + 4) \cdot 5}{15} - \frac{16}{3} = 0$

Subtract $2 x$ from $- 2 x$ .

$\frac{3 x^{2} + 12 x + 12 + (x^{2} - 4 x + 4) \cdot 5}{15} - \frac{16}{3} = 0$

Apply the distributive property.

$\frac{3 x^{2} + 12 x + 12 + x^{2} \cdot 5 - 4 x \cdot 5 + 4 \cdot 5}{15} - \frac{16}{3} = 0$

Simplify.

Move $5$ to the left of $x^{2}$ .

$\frac{3 x^{2} + 12 x + 12 + 5 \cdot x^{2} - 4 x \cdot 5 + 4 \cdot 5}{15} - \frac{16}{3} = 0$

Multiply $5$ by $- 4$ .

$\frac{3 x^{2} + 12 x + 12 + 5 \cdot x^{2} - 20 x + 4 \cdot 5}{15} - \frac{16}{3} = 0$

Multiply $4$ by $5$ .

$\frac{3 x^{2} + 12 x + 12 + 5 \cdot x^{2} - 20 x + 20}{15} - \frac{16}{3} = 0$

Add $3 x^{2}$ and $5 x^{2}$ .

$\frac{8 x^{2} + 12 x + 12 - 20 x + 20}{15} - \frac{16}{3} = 0$

Subtract $20 x$ from $12 x$ .

$\frac{8 x^{2} - 8 x + 12 + 20}{15} - \frac{16}{3} = 0$

Add $12$ and $20$ .

$\frac{8 x^{2} - 8 x + 32}{15} - \frac{16}{3} = 0$

Factor $8$ out of $8 x^{2} - 8 x + 32$ .

Factor $8$ out of $8 x^{2}$ .

$\frac{8 (x^{2}) - 8 x + 32}{15} - \frac{16}{3} = 0$

Factor $8$ out of $- 8 x$ .

$\frac{8 (x^{2}) + 8 (- x) + 32}{15} - \frac{16}{3} = 0$

Factor $8$ out of $32$ .

$\frac{8 (x^{2}) + 8 (- x) + 8 (4)}{15} - \frac{16}{3} = 0$

Factor $8$ out of $8 (x^{2}) + 8 (- x)$ .

$\frac{8 (x^{2} - x) + 8 (4)}{15} - \frac{16}{3} = 0$

Factor $8$ out of $8 (x^{2} - x) + 8 (4)$ .

$\frac{8 (x^{2} - x + 4)}{15} - \frac{16}{3} = 0$

To write $- \frac{16}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{8 (x^{2} - x + 4)}{15} - \frac{16}{3} \cdot \frac{5}{5} = 0$

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{16}{3}$ by $\frac{5}{5}$ .

$\frac{8 (x^{2} - x + 4)}{15} - \frac{16 \cdot 5}{3 \cdot 5} = 0$

Multiply $3$ by $5$ .

$\frac{8 (x^{2} - x + 4)}{15} - \frac{16 \cdot 5}{15} = 0$

Combine the numerators over the common denominator.

$\frac{8 (x^{2} - x + 4) - 16 \cdot 5}{15} = 0$

Simplify the numerator.

Factor $8$ out of $8 (x^{2} - x + 4) - 16 \cdot 5$ .

Factor $8$ out of $- 16 \cdot 5$ .

$\frac{8 (x^{2} - x + 4) + 8 (- 2 \cdot 5)}{15} = 0$

Factor $8$ out of $8 (x^{2} - x + 4) + 8 (- 2 \cdot 5)$ .

$\frac{8 (x^{2} - x + 4 - 2 \cdot 5)}{15} = 0$

Multiply $- 2$ by $5$ .

$\frac{8 (x^{2} - x + 4 - 10)}{15} = 0$

Subtract $10$ from $4$ .

$\frac{8 (x^{2} - x - 6)}{15} = 0$

Factor $x^{2} - x - 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 6$ and whose sum is $- 1$ .

$- 3, 2$

Write the factored form using these integers.

$\frac{8 ((x - 3) (x + 2))}{15} = 0$

$\frac{8 (x - 3) (x + 2)}{15} = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $\frac{8 (x - 3) (x + 2)}{15}$ .

$\frac{8 (x - 3) (x + 2)}{15} = 0$

Step 5

Write in Standard Form ((x+2)^2)/5+((x-2)^2)/3=16/3

Related Questions

Support LCMGCF.com by disabling your adblocker.