Write in Standard Form x^2-36y^2-20x+64=0

$x^{2} - 36 y^{2} - 20 x + 64 = 0$

Subtract $64$ from both sides of the equation.

$x^{2} - 36 y^{2} - 20 x = - 64$

Complete the square for $x^{2} - 20 x$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 20$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 20}{2 \cdot 1}$

Cancel the common factor of $- 20$ and $2$ .

Factor $2$ out of $- 20$ .

$d = \frac{2 \cdot - 10}{2 \cdot 1}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot - 10}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot - 10}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- 10}{1}$

Divide $- 10$ by $1$ .

$d = - 10$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{{(- 20)}^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $- 20$ to the power of $2$ .

$e = 0 - \frac{400}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{400}{4}$

Divide $400$ by $4$ .

$e = 0 - 1 \cdot 100$

Multiply $- 1$ by $100$ .

$e = 0 - 100$

Subtract $100$ from $0$ .

$e = - 100$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x - 10)}^{2} - 100$ .

${(x - 10)}^{2} - 100$

Substitute ${(x - 10)}^{2} - 100$ for $x^{2} - 20 x$ in the equation $x^{2} - 36 y^{2} - 20 x = - 64$ .

${(x - 10)}^{2} - 100 - 36 y^{2} = - 64$

Move $- 100$ to the right side of the equation by adding $100$ to both sides.

${(x - 10)}^{2} - 36 y^{2} = - 64 + 100$

Add $- 64$ and $100$ .

${(x - 10)}^{2} - 36 y^{2} = 36$

Divide each term by $36$ to make the right side equal to one.

$\frac{{(x - 10)}^{2}}{36} - \frac{36 y^{2}}{36} = \frac{36}{36}$

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$\frac{{(x - 10)}^{2}}{36} - \frac{y^{2}}{1} = 1$

Write in Standard Form x^2-36y^2-20x+64=0

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