Write in Standard Form (x^2+9x+18)-(x+6)

$(x^{2} + 9 x + 18) - (x + 6)$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Step 2

Simplify each term.

Apply the distributive property.

$x^{2} + 9 x + 18 - x - 1 \cdot 6$

Multiply $- 1$ by $6$ .

$x^{2} + 9 x + 18 - x - 6$

Step 3

Simplify by adding terms.

Subtract $x$ from $9 x$ .

$x^{2} + 8 x + 18 - 6$

Subtract $6$ from $18$ .

$x^{2} + 8 x + 12$