Write in Standard Form x^2-x+3=4x^2-5

$x^{2} - x + 3 = 4 x^{2} - 5$

Move all the expressions to the left side of the equation.

Subtract $4 x^{2}$ from both sides of the equation.

$x^{2} - x + 3 - 4 x^{2} = - 5$

Add $5$ to both sides of the equation.

$x^{2} - x + 3 - 4 x^{2} + 5 = 0$

Simplify $x^{2} - x + 3 - 4 x^{2} + 5$ .

Subtract $4 x^{2}$ from $x^{2}$ .

$- 3 x^{2} - x + 3 + 5 = 0$

Add $3$ and $5$ .

$- 3 x^{2} - x + 8 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $- 3 x^{2} - x + 8$ .

$- 3 x^{2} - x + 8 = 0$