Write in Standard Form -x^2+x-8=2x

$- x^{2} + x - 8 = 2 x$

Subtract $2 x$ from both sides of the equation.

$- x^{2} + x - 8 - 2 x = 0$

Subtract $2 x$ from $x$ .

$- x^{2} - x - 8 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $- x^{2} - x - 8$ .

$- x^{2} - x - 8 = 0$