Write in Standard Form x^2+y^2-2/5x+5y+5=0

$x^{2} + y^{2} - \frac{2}{5} x + 5 y + 5 = 0$

Step 1

Subtract $5$ from both sides of the equation.

$x^{2} + y^{2} - \frac{2}{5} x + 5 y = - 5$

Step 2

Complete the square for $x^{2} - \frac{2}{5} x$ .

Simplify each term.

Combine $x$ and $\frac{2}{5}$ .

$x^{2} - \frac{x \cdot 2}{5}$

Move $2$ to the left of $x$ .

$x^{2} - \frac{2 x}{5}$

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - \frac{2}{5}$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- \frac{2}{5}}{2 \cdot 1}$

Simplify the right side.

Cancel the common factor of $- 1$ and $1$ .

Rewrite $- 1$ as $- 1 (1)$ .

$d = \frac{- 1 (1) \frac{2}{5}}{2 \cdot 1}$

Cancel the common factor.

$d = \frac{- 1 \cdot 1 \frac{2}{5}}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- \frac{2}{5}}{2}$

Multiply the numerator by the reciprocal of the denominator.

$d = - \frac{2}{5} \cdot \frac{1}{2}$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{2}{5}$ into the numerator.

$d = \frac{- 2}{5} \cdot \frac{1}{2}$

Factor $2$ out of $- 2$ .

$d = \frac{2 (- 1)}{5} \cdot \frac{1}{2}$

Cancel the common factor.

$d = \frac{2 \cdot - 1}{5} \cdot \frac{1}{2}$

Rewrite the expression.

$d = \frac{- 1}{5}$

Move the negative in front of the fraction.

$d = - \frac{1}{5}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{{(- \frac{2}{5})}^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Simplify the numerator.

Apply the product rule to $- \frac{2}{5}$ .

$e = 0 - \frac{{(- 1)}^{2} {(\frac{2}{5})}^{2}}{4 \cdot 1}$

Raise $- 1$ to the power of $2$ .

$e = 0 - \frac{1 {(\frac{2}{5})}^{2}}{4 \cdot 1}$

Apply the product rule to $\frac{2}{5}$ .

$e = 0 - \frac{1 \frac{2^{2}}{5^{2}}}{4 \cdot 1}$

Raise $2$ to the power of $2$ .

$e = 0 - \frac{1 \frac{4}{5^{2}}}{4 \cdot 1}$

Raise $5$ to the power of $2$ .

$e = 0 - \frac{1 (\frac{4}{25})}{4 \cdot 1}$

Multiply $\frac{4}{25}$ by $1$ .

$e = 0 - \frac{\frac{4}{25}}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{\frac{4}{25}}{4}$

Multiply the numerator by the reciprocal of the denominator.

$e = 0 - (\frac{4}{25} \cdot \frac{1}{4})$

Cancel the common factor of $4$ .

Cancel the common factor.

$e = 0 - (\frac{4}{25} \cdot \frac{1}{4})$

Rewrite the expression.

$e = 0 - \frac{1}{25}$

Subtract $\frac{1}{25}$ from $0$ .

$e = - \frac{1}{25}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x - \frac{1}{5})}^{2} - \frac{1}{25}$ .

${(x - \frac{1}{5})}^{2} - \frac{1}{25}$

Step 3

Substitute ${(x - \frac{1}{5})}^{2} - \frac{1}{25}$ for $x^{2} - \frac{2}{5} x$ in the equation $x^{2} + y^{2} - \frac{2}{5} x + 5 y = - 5$ .

${(x - \frac{1}{5})}^{2} - \frac{1}{25} + y^{2} + 5 y = - 5$

Step 4

Move $- \frac{1}{25}$ to the right side of the equation by adding $\frac{1}{25}$ to both sides.

${(x - \frac{1}{5})}^{2} + y^{2} + 5 y = - 5 + \frac{1}{25}$

Step 5

Complete the square for $y^{2} + 5 y$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 5$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{5}{2 \cdot 1}$

Multiply $2$ by $1$ .

$d = \frac{5}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{5^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $5$ to the power of $2$ .

$e = 0 - \frac{25}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{25}{4}$

Subtract $\frac{25}{4}$ from $0$ .

$e = - \frac{25}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(y + \frac{5}{2})}^{2} - \frac{25}{4}$ .

${(y + \frac{5}{2})}^{2} - \frac{25}{4}$

Step 6

Substitute ${(y + \frac{5}{2})}^{2} - \frac{25}{4}$ for $y^{2} + 5 y$ in the equation $x^{2} + y^{2} - \frac{2}{5} x + 5 y = - 5$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} - \frac{25}{4} = - 5 + \frac{1}{25}$

Step 7

Move $- \frac{25}{4}$ to the right side of the equation by adding $\frac{25}{4}$ to both sides.

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = - 5 + \frac{1}{25} + \frac{25}{4}$

Step 8

Simplify $- 5 + \frac{1}{25} + \frac{25}{4}$ .

Find the common denominator.

Write $- 5$ as a fraction with denominator $1$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5}{1} + \frac{1}{25} + \frac{25}{4}$

Multiply $\frac{- 5}{1}$ by $\frac{100}{100}$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5}{1} \cdot \frac{100}{100} + \frac{1}{25} + \frac{25}{4}$

Multiply $\frac{- 5}{1}$ by $\frac{100}{100}$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{1}{25} + \frac{25}{4}$

Multiply $\frac{1}{25}$ by $\frac{4}{4}$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{1}{25} \cdot \frac{4}{4} + \frac{25}{4}$

Multiply $\frac{1}{25}$ by $\frac{4}{4}$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{4}{25 \cdot 4} + \frac{25}{4}$

Multiply $\frac{25}{4}$ by $\frac{25}{25}$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{4}{25 \cdot 4} + \frac{25}{4} \cdot \frac{25}{25}$

Multiply $\frac{25}{4}$ by $\frac{25}{25}$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{4}{25 \cdot 4} + \frac{25 \cdot 25}{4 \cdot 25}$

Reorder the factors of $25 \cdot 4$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{4}{4 \cdot 25} + \frac{25 \cdot 25}{4 \cdot 25}$

Multiply $4$ by $25$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{4}{100} + \frac{25 \cdot 25}{4 \cdot 25}$

Multiply $4$ by $25$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100}{100} + \frac{4}{100} + \frac{25 \cdot 25}{100}$

Combine the numerators over the common denominator.

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 5 \cdot 100 + 4 + 25 \cdot 25}{100}$

Simplify each term.

Multiply $- 5$ by $100$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 500 + 4 + 25 \cdot 25}{100}$

Multiply $25$ by $25$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 500 + 4 + 625}{100}$

Simplify by adding numbers.

Add $- 500$ and $4$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{- 496 + 625}{100}$

Add $- 496$ and $625$ .

${(x - \frac{1}{5})}^{2} + {(y + \frac{5}{2})}^{2} = \frac{129}{100}$

Write in Standard Form x^2+y^2-2/5x+5y+5=0

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