Write in Standard Form (x-3)^2=0

${(x - 3)}^{2} = 0$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 2

Rewrite ${(x - 3)}^{2}$ as $(x - 3) (x - 3)$ .

$(x - 3) (x - 3) = 0$

Step 3

Expand $(x - 3) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$x (x - 3) - 3 (x - 3) = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 3 - 3 (x - 3) = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 3 - 3 x - 3 \cdot - 3 = 0$

Step 4

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 3 - 3 x - 3 \cdot - 3 = 0$

Move $- 3$ to the left of $x$ .

$x^{2} - 3 \cdot x - 3 x - 3 \cdot - 3 = 0$

Multiply $- 3$ by $- 3$ .

$x^{2} - 3 x - 3 x + 9 = 0$

Subtract $3 x$ from $- 3 x$ .

$x^{2} - 6 x + 9 = 0$

Step 5