Write in Standard Form (x-3)^2-2x=9

${(x - 3)}^{2} - 2 x = 9$

Subtract $9$ from both sides of the equation.

${(x - 3)}^{2} - 2 x - 9 = 0$

Simplify ${(x - 3)}^{2} - 2 x - 9$ .

Simplify each term.

Rewrite ${(x - 3)}^{2}$ as $(x - 3) (x - 3)$ .

$(x - 3) (x - 3) - 2 x - 9 = 0$

Expand $(x - 3) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$x (x - 3) - 3 (x - 3) - 2 x - 9 = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 3 - 3 (x - 3) - 2 x - 9 = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 3 - 3 x - 3 \cdot - 3 - 2 x - 9 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 3 - 3 x - 3 \cdot - 3 - 2 x - 9 = 0$

Move $- 3$ to the left of $x$ .

$x^{2} - 3 \cdot x - 3 x - 3 \cdot - 3 - 2 x - 9 = 0$

Multiply $- 3$ by $- 3$ .

$x^{2} - 3 x - 3 x + 9 - 2 x - 9 = 0$

Subtract $3 x$ from $- 3 x$ .

$x^{2} - 6 x + 9 - 2 x - 9 = 0$

Combine the opposite terms in $x^{2} - 6 x + 9 - 2 x - 9$ .

Subtract $9$ from $9$ .

$x^{2} - 6 x - 2 x + 0 = 0$

Add $x^{2} - 6 x - 2 x$ and $0$ .

$x^{2} - 6 x - 2 x = 0$

Subtract $2 x$ from $- 6 x$ .

$x^{2} - 8 x = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $x^{2} - 8 x$ .

$x^{2} - 8 x = 0$