Write in Standard Form (x+4)^2=5

${(x + 4)}^{2} = 5$

Subtract $5$ from both sides of the equation.

${(x + 4)}^{2} - 5 = 0$

Simplify ${(x + 4)}^{2} - 5$ .

Simplify each term.

Rewrite ${(x + 4)}^{2}$ as $(x + 4) (x + 4)$ .

$(x + 4) (x + 4) - 5 = 0$

Expand $(x + 4) (x + 4)$ using the FOIL Method.

Apply the distributive property.

$x (x + 4) + 4 (x + 4) - 5 = 0$

Apply the distributive property.

$x \cdot x + x \cdot 4 + 4 (x + 4) - 5 = 0$

Apply the distributive property.

$x \cdot x + x \cdot 4 + 4 x + 4 \cdot 4 - 5 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 4 + 4 x + 4 \cdot 4 - 5 = 0$

Move $4$ to the left of $x$ .

$x^{2} + 4 \cdot x + 4 x + 4 \cdot 4 - 5 = 0$

Multiply $4$ by $4$ .

$x^{2} + 4 x + 4 x + 16 - 5 = 0$

Add $4 x$ and $4 x$ .

$x^{2} + 8 x + 16 - 5 = 0$

Subtract $5$ from $16$ .

$x^{2} + 8 x + 11 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $x^{2} + 8 x + 11$ .

$x^{2} + 8 x + 11 = 0$