Write in Standard Form (x+5)(2x-3)=2(x+1)

$(x + 5) (2 x - 3) = 2 (x + 1)$

Subtract $2 (x + 1)$ from both sides of the equation.

$(x + 5) (2 x - 3) - 2 (x + 1) = 0$

Simplify $(x + 5) (2 x - 3) - 2 (x + 1)$ .

Simplify each term.

Expand $(x + 5) (2 x - 3)$ using the FOIL Method.

Apply the distributive property.

$x (2 x - 3) + 5 (2 x - 3) - 2 (x + 1) = 0$

Apply the distributive property.

$x (2 x) + x \cdot - 3 + 5 (2 x - 3) - 2 (x + 1) = 0$

Apply the distributive property.

$x (2 x) + x \cdot - 3 + 5 (2 x) + 5 \cdot - 3 - 2 (x + 1) = 0$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$2 x \cdot x + x \cdot - 3 + 5 (2 x) + 5 \cdot - 3 - 2 (x + 1) = 0$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$2 (x \cdot x) + x \cdot - 3 + 5 (2 x) + 5 \cdot - 3 - 2 (x + 1) = 0$

Multiply $x$ by $x$ .

$2 x^{2} + x \cdot - 3 + 5 (2 x) + 5 \cdot - 3 - 2 (x + 1) = 0$

Move $- 3$ to the left of $x$ .

$2 x^{2} - 3 \cdot x + 5 (2 x) + 5 \cdot - 3 - 2 (x + 1) = 0$

Multiply $2$ by $5$ .

$2 x^{2} - 3 x + 10 x + 5 \cdot - 3 - 2 (x + 1) = 0$

Multiply $5$ by $- 3$ .

$2 x^{2} - 3 x + 10 x - 15 - 2 (x + 1) = 0$

Add $- 3 x$ and $10 x$ .

$2 x^{2} + 7 x - 15 - 2 (x + 1) = 0$

Apply the distributive property.

$2 x^{2} + 7 x - 15 - 2 x - 2 \cdot 1 = 0$

Multiply $- 2$ by $1$ .

$2 x^{2} + 7 x - 15 - 2 x - 2 = 0$

Subtract $2 x$ from $7 x$ .

$2 x^{2} + 5 x - 15 - 2 = 0$

Subtract $2$ from $- 15$ .

$2 x^{2} + 5 x - 17 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $2 x^{2} + 5 x - 17$ .

$2 x^{2} + 5 x - 17 = 0$