Write in Standard Form (x-5)(x+3)-8=7

$(x - 5) (x + 3) - 8 = 7$

Step 1

Subtract $7$ from both sides of the equation.

$(x - 5) (x + 3) - 8 - 7 = 0$

Step 2

Simplify $(x - 5) (x + 3) - 8 - 7$ .

Simplify each term.

Expand $(x - 5) (x + 3)$ using the FOIL Method.

Apply the distributive property.

$x (x + 3) - 5 (x + 3) - 8 - 7 = 0$

Apply the distributive property.

$x \cdot x + x \cdot 3 - 5 (x + 3) - 8 - 7 = 0$

Apply the distributive property.

$x \cdot x + x \cdot 3 - 5 x - 5 \cdot 3 - 8 - 7 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 3 - 5 x - 5 \cdot 3 - 8 - 7 = 0$

Move $3$ to the left of $x$ .

$x^{2} + 3 \cdot x - 5 x - 5 \cdot 3 - 8 - 7 = 0$

Multiply $- 5$ by $3$ .

$x^{2} + 3 x - 5 x - 15 - 8 - 7 = 0$

Subtract $5 x$ from $3 x$ .

$x^{2} - 2 x - 15 - 8 - 7 = 0$

Subtract $8$ from $- 15$ .

$x^{2} - 2 x - 23 - 7 = 0$

Subtract $7$ from $- 23$ .

$x^{2} - 2 x - 30 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $x^{2} - 2 x - 30$ .

$x^{2} - 2 x - 30 = 0$

Step 5