Write in Standard Form -x/9+8x^3-1

$- \frac{x}{9} + 8 x^{3} - 1$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Reorder $- \frac{x}{9}$ and $8 x^{3}$ .

$8 x^{3} - \frac{x}{9} - 1$

Reorder terms.

$8 x^{3} - (\frac{1}{9} x) - 1$

Remove parentheses.

$8 x^{3} - \frac{1}{9} x - 1$