Write in Standard Form x(x+1)=12

$x (x + 1) = 12$

Subtract $12$ from both sides of the equation.

$x (x + 1) - 12 = 0$

Simplify each term.

Apply the distributive property.

$x \cdot x + x \cdot 1 - 12 = 0$

Multiply $x$ by $x$ .

$x^{2} + x \cdot 1 - 12 = 0$

Multiply $x$ by $1$ .

$x^{2} + x - 12 = 0$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

The standard form is $x^{2} + x - 12$ .

$x^{2} + x - 12 = 0$