Write in Standard Form x(x-4)(x-6)=0

$x (x - 4) (x - 6) = 0$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 2

Simplify by multiplying through.

Apply the distributive property.

$(x \cdot x + x \cdot - 4) (x - 6) = 0$

Simplify the expression.

Multiply $x$ by $x$ .

$(x^{2} + x \cdot - 4) (x - 6) = 0$

Move $- 4$ to the left of $x$ .

$(x^{2} - 4 \cdot x) (x - 6) = 0$

Step 3

Expand $(x^{2} - 4 x) (x - 6)$ using the FOIL Method.

Apply the distributive property.

$x^{2} (x - 6) - 4 x (x - 6) = 0$

Apply the distributive property.

$x^{2} x + x^{2} \cdot - 6 - 4 x (x - 6) = 0$

Apply the distributive property.

$x^{2} x + x^{2} \cdot - 6 - 4 x \cdot x - 4 x \cdot - 6 = 0$

Step 4

Simplify and combine like terms.

Simplify each term.

Multiply $x^{2}$ by $x$ by adding the exponents.

Multiply $x^{2}$ by $x$ .

Raise $x$ to the power of $1$ .

$x^{2} x + x^{2} \cdot - 6 - 4 x \cdot x - 4 x \cdot - 6 = 0$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{2 + 1} + x^{2} \cdot - 6 - 4 x \cdot x - 4 x \cdot - 6 = 0$

Add $2$ and $1$ .

$x^{3} + x^{2} \cdot - 6 - 4 x \cdot x - 4 x \cdot - 6 = 0$

Move $- 6$ to the left of $x^{2}$ .

$x^{3} - 6 \cdot x^{2} - 4 x \cdot x - 4 x \cdot - 6 = 0$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$x^{3} - 6 x^{2} - 4 (x \cdot x) - 4 x \cdot - 6 = 0$

Multiply $x$ by $x$ .

$x^{3} - 6 x^{2} - 4 x^{2} - 4 x \cdot - 6 = 0$

Multiply $- 6$ by $- 4$ .

$x^{3} - 6 x^{2} - 4 x^{2} + 24 x = 0$

Subtract $4 x^{2}$ from $- 6 x^{2}$ .

$x^{3} - 10 x^{2} + 24 x = 0$

Step 5