Write in Standard Form x=(y+5)^2-9

$x = {(y + 5)}^{2} - 9$

Step 1

Solve for $y$ .

Rewrite the equation as ${(y + 5)}^{2} - 9 = x$ .

${(y + 5)}^{2} - 9 = x$

Add $9$ to both sides of the equation.

${(y + 5)}^{2} = x + 9$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$y + 5 = \pm \sqrt{x + 9}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y + 5 = \sqrt{x + 9}$

Subtract $5$ from both sides of the equation.

$y = \sqrt{x + 9} - 5$

Next, use the negative value of the $\pm$ to find the second solution.

$y + 5 = - \sqrt{x + 9}$

Subtract $5$ from both sides of the equation.

$y = - \sqrt{x + 9} - 5$

The complete solution is the result of both the positive and negative portions of the solution.

$y = \sqrt{x + 9} - 5$

$y = - \sqrt{x + 9} - 5$

$y = \sqrt{x + 9} - 5$

$y = - \sqrt{x + 9} - 5$

$y = \sqrt{x + 9} - 5$

$y = - \sqrt{x + 9} - 5$

Step 2

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$y = a x^{2} + b x + c$

Step 3

The standard form is $\sqrt{x + 9} - 5, - \sqrt{x + 9} - 5$ .

$y = \sqrt{x + 9} - 5$

$y = - \sqrt{x + 9} - 5$

Step 4