Write in Standard Form y+3=-1/3(2x+6)

$y + 3 = - \frac{1}{3} (2 x + 6)$

The standard form of a linear equation is $A x + B y = C$ .

Multiply both sides by $3$ .

$3 (y + 3) = 3 (- \frac{1}{3} (2 x + 6))$

Simplify the left side.

Simplify $3 (y + 3)$ .

Apply the distributive property.

$3 y + 3 \cdot 3 = 3 (- \frac{1}{3} (2 x + 6))$

Multiply $3$ by $3$ .

$3 y + 9 = 3 (- \frac{1}{3} (2 x + 6))$

Simplify the right side.

Simplify $3 (- \frac{1}{3} (2 x + 6))$ .

Apply the distributive property.

$3 y + 9 = 3 (- \frac{1}{3} (2 x) - \frac{1}{3} \cdot 6)$

Multiply $- \frac{1}{3} (2 x)$ .

Multiply $2$ by $- 1$ .

$3 y + 9 = 3 (- 2 (\frac{1}{3}) x - \frac{1}{3} \cdot 6)$

Combine $- 2$ and $\frac{1}{3}$ .

$3 y + 9 = 3 (\frac{- 2}{3} x - \frac{1}{3} \cdot 6)$

Combine $\frac{- 2}{3}$ and $x$ .

$3 y + 9 = 3 (\frac{- 2 x}{3} - \frac{1}{3} \cdot 6)$

Reduce the expression by cancelling the common factors.

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{1}{3}$ into the numerator.

$3 y + 9 = 3 (\frac{- 2 x}{3} + \frac{- 1}{3} \cdot 6)$

Factor $3$ out of $6$ .

$3 y + 9 = 3 (\frac{- 2 x}{3} + \frac{- 1}{3} \cdot (3 (2)))$

Cancel the common factor.

$3 y + 9 = 3 (\frac{- 2 x}{3} + \frac{- 1}{3} \cdot (3 \cdot 2))$

Rewrite the expression.

$3 y + 9 = 3 (\frac{- 2 x}{3} - 1 \cdot 2)$

Multiply $- 1$ by $2$ .

$3 y + 9 = 3 (\frac{- 2 x}{3} - 2)$

Move the negative in front of the fraction.

$3 y + 9 = 3 (- \frac{2 x}{3} - 2)$

Simplify terms.

Apply the distributive property.

$3 y + 9 = 3 (- \frac{2 x}{3}) + 3 \cdot - 2$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{2 x}{3}$ into the numerator.

$3 y + 9 = 3 \frac{- 2 x}{3} + 3 \cdot - 2$

Cancel the common factor.

$3 y + 9 = 3 \frac{- 2 x}{3} + 3 \cdot - 2$

Rewrite the expression.

$3 y + 9 = - 2 x + 3 \cdot - 2$

Multiply $3$ by $- 2$ .

$3 y + 9 = - 2 x - 6$

Move all terms containing variables to the left side of the equation.

Add $2 x$ to both sides of the equation.

$3 y + 9 + 2 x = - 6$

Move $9$ .

$3 y + 2 x + 9 = - 6$

Reorder $3 y$ and $2 x$ .

$2 x + 3 y + 9 = - 6$

Move all terms not containing a variable to the right side of the equation.

Subtract $9$ from both sides of the equation.

$2 x + 3 y = - 6 - 9$

Subtract $9$ from $- 6$ .

$2 x + 3 y = - 15$

Write in Standard Form y+3=-1/3(2x+6)

Related Questions

Support LCMGCF.com by disabling your adblocker.