Write in y=mx+b Form 12x-4y=3

$12 x - 4 y = 3$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Subtract $12 x$ from both sides of the equation.

$- 4 y = 3 - 12 x$

Divide each term in $- 4 y = 3 - 12 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = 3 - 12 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{3}{- 4} + \frac{- 12 x}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{3}{- 4} + \frac{- 12 x}{- 4}$

Divide $y$ by $1$ .

$y = \frac{3}{- 4} + \frac{- 12 x}{- 4}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{3}{4} + \frac{- 12 x}{- 4}$

Cancel the common factor of $- 12$ and $- 4$ .

Factor $- 4$ out of $- 12 x$ .

$y = - \frac{3}{4} + \frac{- 4 (3 x)}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = - \frac{3}{4} + \frac{- 4 (3 x)}{- 4 (1)}$

Cancel the common factor.

$y = - \frac{3}{4} + \frac{- 4 (3 x)}{- 4 \cdot 1}$

Rewrite the expression.

$y = - \frac{3}{4} + \frac{3 x}{1}$

Divide $3 x$ by $1$ .

$y = - \frac{3}{4} + 3 x$

Reorder $- \frac{3}{4}$ and $3 x$ .

$y = 3 x - \frac{3}{4}$