Write in y=mx+b Form 16x-4y-12=0

$16 x - 4 y - 12 = 0$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Move all terms not containing $y$ to the right side of the equation.

Subtract $16 x$ from both sides of the equation.

$- 4 y - 12 = - 16 x$

Add $12$ to both sides of the equation.

$- 4 y = - 16 x + 12$

Divide each term in $- 4 y = - 16 x + 12$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 16 x + 12$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 16 x}{- 4} + \frac{12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 16 x}{- 4} + \frac{12}{- 4}$

Divide $y$ by $1$ .

$y = \frac{- 16 x}{- 4} + \frac{12}{- 4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 16$ and $- 4$ .

Factor $- 4$ out of $- 16 x$ .

$y = \frac{- 4 (4 x)}{- 4} + \frac{12}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = \frac{- 4 (4 x)}{- 4 (1)} + \frac{12}{- 4}$

Cancel the common factor.

$y = \frac{- 4 (4 x)}{- 4 \cdot 1} + \frac{12}{- 4}$

Rewrite the expression.

$y = \frac{4 x}{1} + \frac{12}{- 4}$

Divide $4 x$ by $1$ .

$y = 4 x + \frac{12}{- 4}$

Divide $12$ by $- 4$ .

$y = 4 x - 3$