Write in y=mx+b Form 2-(2y+8x)/3=1

$2 - \frac{2 y + 8 x}{3} = 1$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Simplify the left side.

Simplify $2 - \frac{2 y + 8 x}{3}$ .

Factor $2$ out of $2 y + 8 x$ .

Factor $2$ out of $2 y$ .

$2 - \frac{2 (y) + 8 x}{3} = 1$

Factor $2$ out of $8 x$ .

$2 - \frac{2 (y) + 2 (4 x)}{3} = 1$

Factor $2$ out of $2 (y) + 2 (4 x)$ .

$2 - \frac{2 (y + 4 x)}{3} = 1$

To write $2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 \cdot \frac{3}{3} - \frac{2 (y + 4 x)}{3} = 1$

Simplify terms.

Combine $2$ and $\frac{3}{3}$ .

$\frac{2 \cdot 3}{3} - \frac{2 (y + 4 x)}{3} = 1$

Combine the numerators over the common denominator.

$\frac{2 \cdot 3 - 2 (y + 4 x)}{3} = 1$

Simplify the numerator.

Factor $2$ out of $2 \cdot 3 - 2 (y + 4 x)$ .

Factor $2$ out of $2 \cdot 3$ .

$\frac{2 (3) - 2 (y + 4 x)}{3} = 1$

Factor $2$ out of $- 2 (y + 4 x)$ .

$\frac{2 (3) + 2 (- (y + 4 x))}{3} = 1$

Factor $2$ out of $2 (3) + 2 (- (y + 4 x))$ .

$\frac{2 (3 - (y + 4 x))}{3} = 1$

Apply the distributive property.

$\frac{2 (3 - y - (4 x))}{3} = 1$

Multiply $4$ by $- 1$ .

$\frac{2 (3 - y - 4 x)}{3} = 1$

Multiply both sides by $3$ .

$\frac{2 (3 - y - 4 x)}{3} \cdot 3 = 1 \cdot 3$

Simplify.

Simplify the left side.

Simplify $\frac{2 (3 - y - 4 x)}{3} \cdot 3$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{2 (3 - y - 4 x)}{3} \cdot 3 = 1 \cdot 3$

Rewrite the expression.

$2 (3 - y - 4 x) = 1 \cdot 3$

Apply the distributive property.

$2 \cdot 3 + 2 (- y) + 2 (- 4 x) = 1 \cdot 3$

Simplify.

Multiply $2$ by $3$ .

$6 + 2 (- y) + 2 (- 4 x) = 1 \cdot 3$

Multiply $- 1$ by $2$ .

$6 - 2 y + 2 (- 4 x) = 1 \cdot 3$

Multiply $- 4$ by $2$ .

$6 - 2 y - 8 x = 1 \cdot 3$

Move $6$ .

$- 2 y - 8 x + 6 = 1 \cdot 3$

Reorder $- 2 y$ and $- 8 x$ .

$- 8 x - 2 y + 6 = 1 \cdot 3$

Simplify the right side.

Multiply $3$ by $1$ .

$- 8 x - 2 y + 6 = 3$

Solve for $y$ .

Move all terms not containing $y$ to the right side of the equation.

Add $8 x$ to both sides of the equation.

$- 2 y + 6 = 3 + 8 x$

Subtract $6$ from both sides of the equation.

$- 2 y = 3 + 8 x - 6$

Subtract $6$ from $3$ .

$- 2 y = 8 x - 3$

Divide each term in $- 2 y = 8 x - 3$ by $- 2$ and simplify.

Divide each term in $- 2 y = 8 x - 3$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{8 x}{- 2} + \frac{- 3}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{8 x}{- 2} + \frac{- 3}{- 2}$

Divide $y$ by $1$ .

$y = \frac{8 x}{- 2} + \frac{- 3}{- 2}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $8$ and $- 2$ .

Factor $2$ out of $8 x$ .

$y = \frac{2 (4 x)}{- 2} + \frac{- 3}{- 2}$

Move the negative one from the denominator of $\frac{4 x}{- 1}$ .

$y = - 1 \cdot (4 x) + \frac{- 3}{- 2}$

Rewrite $- 1 \cdot (4 x)$ as $- (4 x)$ .

$y = - (4 x) + \frac{- 3}{- 2}$

Multiply $4$ by $- 1$ .

$y = - 4 x + \frac{- 3}{- 2}$

Dividing two negative values results in a positive value.

$y = - 4 x + \frac{3}{2}$

Write in y=mx+b Form 2-(2y+8x)/3=1

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