Write in y=mx+b Form -2/3x-2y=-2

$- \frac{2}{3} x - 2 y = - 2$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Simplify the left side.

Simplify each term.

Combine $x$ and $\frac{2}{3}$ .

$- \frac{x \cdot 2}{3} - 2 y = - 2$

Move $2$ to the left of $x$ .

$- \frac{2 x}{3} - 2 y = - 2$

Add $\frac{2 x}{3}$ to both sides of the equation.

$- 2 y = - 2 + \frac{2 x}{3}$

Divide each term in $- 2 y = - 2 + \frac{2 x}{3}$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 2 + \frac{2 x}{3}$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 2}{- 2} + \frac{\frac{2 x}{3}}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 2}{- 2} + \frac{\frac{2 x}{3}}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 2}{- 2} + \frac{\frac{2 x}{3}}{- 2}$

Simplify the right side.

Simplify each term.

Divide $- 2$ by $- 2$ .

$y = 1 + \frac{\frac{2 x}{3}}{- 2}$

Multiply the numerator by the reciprocal of the denominator.

$y = 1 + \frac{2 x}{3} \cdot \frac{1}{- 2}$

Cancel the common factor of $2$ .

Factor $2$ out of $2 x$ .

$y = 1 + \frac{2 (x)}{3} \cdot \frac{1}{- 2}$

Factor $2$ out of $- 2$ .

$y = 1 + \frac{2 (x)}{3} \cdot \frac{1}{2 (- 1)}$

Cancel the common factor.

$y = 1 + \frac{2 x}{3} \cdot \frac{1}{2 \cdot - 1}$

Rewrite the expression.

$y = 1 + \frac{x}{3} \cdot \frac{1}{- 1}$

Multiply $\frac{x}{3}$ by $\frac{1}{- 1}$ .

$y = 1 + \frac{x}{3 \cdot - 1}$

Multiply $3$ by $- 1$ .

$y = 1 + \frac{x}{- 3}$

Move the negative in front of the fraction.

$y = 1 - \frac{x}{3}$

Write in $y = m x + b$ form.

Reorder $1$ and $- \frac{x}{3}$ .

$y = - \frac{x}{3} + 1$

Reorder terms.

$y = - (\frac{1}{3} x) + 1$

Remove parentheses.

$y = - \frac{1}{3} x + 1$

Write in y=mx+b Form -2/3x-2y=-2

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