Write in y=mx+b Form (2x-4y)/2=(2x-3)/4

$\frac{2 x - 4 y}{2} = \frac{2 x - 3}{4}$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Simplify the left side.

Cancel the common factor of $2 x - 4 y$ and $2$ .

Factor $2$ out of $2 x$ .

$\frac{2 (x) - 4 y}{2} = \frac{2 x - 3}{4}$

Factor $2$ out of $- 4 y$ .

$\frac{2 (x) + 2 (- 2 y)}{2} = \frac{2 x - 3}{4}$

Factor $2$ out of $2 (x) + 2 (- 2 y)$ .

$\frac{2 (x - 2 y)}{2} = \frac{2 x - 3}{4}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 (x - 2 y)}{2 (1)} = \frac{2 x - 3}{4}$

Cancel the common factor.

$\frac{2 (x - 2 y)}{2 \cdot 1} = \frac{2 x - 3}{4}$

Rewrite the expression.

$\frac{x - 2 y}{1} = \frac{2 x - 3}{4}$

Divide $x - 2 y$ by $1$ .

$x - 2 y = \frac{2 x - 3}{4}$

Simplify $\frac{2 x - 3}{4}$ .

Split the fraction $\frac{2 x - 3}{4}$ into two fractions.

$x - 2 y = \frac{2 x}{4} + \frac{- 3}{4}$

Simplify each term.

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2 x$ .

$x - 2 y = \frac{2 (x)}{4} + \frac{- 3}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x - 2 y = \frac{2 x}{2 \cdot 2} + \frac{- 3}{4}$

Cancel the common factor.

$x - 2 y = \frac{2 x}{2 \cdot 2} + \frac{- 3}{4}$

Rewrite the expression.

$x - 2 y = \frac{x}{2} + \frac{- 3}{4}$

Move the negative in front of the fraction.

$x - 2 y = \frac{x}{2} - \frac{3}{4}$

Subtract $x$ from both sides of the equation.

$- 2 y = \frac{x}{2} - \frac{3}{4} - x$

Divide each term in $- 2 y = \frac{x}{2} - \frac{3}{4} - x$ by $- 2$ and simplify.

Divide each term in $- 2 y = \frac{x}{2} - \frac{3}{4} - x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{\frac{x}{2}}{- 2} + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{\frac{x}{2}}{- 2} + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Divide $y$ by $1$ .

$y = \frac{\frac{x}{2}}{- 2} + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Simplify the right side.

Simplify each term.

Multiply the numerator by the reciprocal of the denominator.

$y = \frac{x}{2} \cdot \frac{1}{- 2} + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Move the negative in front of the fraction.

$y = \frac{x}{2} (- \frac{1}{2}) + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Multiply $\frac{x}{2} (- \frac{1}{2})$ .

Multiply $\frac{x}{2}$ by $\frac{1}{2}$ .

$y = - \frac{x}{2 \cdot 2} + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Multiply $2$ by $2$ .

$y = - \frac{x}{4} + \frac{- \frac{3}{4}}{- 2} + \frac{- x}{- 2}$

Multiply the numerator by the reciprocal of the denominator.

$y = - \frac{x}{4} - \frac{3}{4} \cdot \frac{1}{- 2} + \frac{- x}{- 2}$

Move the negative in front of the fraction.

$y = - \frac{x}{4} - \frac{3}{4} (- \frac{1}{2}) + \frac{- x}{- 2}$

Multiply $- \frac{3}{4} (- \frac{1}{2})$ .

Multiply $- 1$ by $- 1$ .

$y = - \frac{x}{4} + 1 (\frac{3}{4}) \frac{1}{2} + \frac{- x}{- 2}$

Multiply $\frac{3}{4}$ by $1$ .

$y = - \frac{x}{4} + \frac{3}{4} \cdot \frac{1}{2} + \frac{- x}{- 2}$

Multiply $\frac{3}{4}$ by $\frac{1}{2}$ .

$y = - \frac{x}{4} + \frac{3}{4 \cdot 2} + \frac{- x}{- 2}$

Multiply $4$ by $2$ .

$y = - \frac{x}{4} + \frac{3}{8} + \frac{- x}{- 2}$

Dividing two negative values results in a positive value.

$y = - \frac{x}{4} + \frac{3}{8} + \frac{x}{2}$

Write in $y = m x + b$ form.

Simplify $- \frac{x}{4} + \frac{3}{8} + \frac{x}{2}$ .

To write $\frac{x}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = - \frac{x}{4} + \frac{x}{2} \cdot \frac{2}{2} + \frac{3}{8}$

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{x}{2}$ by $\frac{2}{2}$ .

$y = - \frac{x}{4} + \frac{x \cdot 2}{2 \cdot 2} + \frac{3}{8}$

Multiply $2$ by $2$ .

$y = - \frac{x}{4} + \frac{x \cdot 2}{4} + \frac{3}{8}$

Combine the numerators over the common denominator.

$y = \frac{- x + x \cdot 2}{4} + \frac{3}{8}$

Add $- x$ and $x \cdot 2$ .

Reorder $x$ and $2$ .

$y = \frac{- x + 2 \cdot x}{4} + \frac{3}{8}$

Add $- x$ and $2 \cdot x$ .

$y = \frac{x}{4} + \frac{3}{8}$

Reorder terms.

$y = \frac{1}{4} x + \frac{3}{8}$

Write in y=mx+b Form (2x-4y)/2=(2x-3)/4

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