Write in y=mx+b Form 8x-2y-4=0

$8 x - 2 y - 4 = 0$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Move all terms not containing $y$ to the right side of the equation.

Subtract $8 x$ from both sides of the equation.

$- 2 y - 4 = - 8 x$

Add $4$ to both sides of the equation.

$- 2 y = - 8 x + 4$

Divide each term in $- 2 y = - 8 x + 4$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 8 x + 4$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 8 x}{- 2} + \frac{4}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 8 x}{- 2} + \frac{4}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 8 x}{- 2} + \frac{4}{- 2}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 8$ and $- 2$ .

Factor $- 2$ out of $- 8 x$ .

$y = \frac{- 2 (4 x)}{- 2} + \frac{4}{- 2}$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$y = \frac{- 2 (4 x)}{- 2 (1)} + \frac{4}{- 2}$

Cancel the common factor.

$y = \frac{- 2 (4 x)}{- 2 \cdot 1} + \frac{4}{- 2}$

Rewrite the expression.

$y = \frac{4 x}{1} + \frac{4}{- 2}$

Divide $4 x$ by $1$ .

$y = 4 x + \frac{4}{- 2}$

Divide $4$ by $- 2$ .

$y = 4 x - 2$