Write in y=mx+b Form 9x-3y-12=0

$9 x - 3 y - 12 = 0$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

Move all terms not containing $y$ to the right side of the equation.

Subtract $9 x$ from both sides of the equation.

$- 3 y - 12 = - 9 x$

Add $12$ to both sides of the equation.

$- 3 y = - 9 x + 12$

Divide each term in $- 3 y = - 9 x + 12$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 9 x + 12$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 9 x}{- 3} + \frac{12}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 9 x}{- 3} + \frac{12}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 9 x}{- 3} + \frac{12}{- 3}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 9$ and $- 3$ .

Factor $- 3$ out of $- 9 x$ .

$y = \frac{- 3 (3 x)}{- 3} + \frac{12}{- 3}$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = \frac{- 3 (3 x)}{- 3 (1)} + \frac{12}{- 3}$

Cancel the common factor.

$y = \frac{- 3 (3 x)}{- 3 \cdot 1} + \frac{12}{- 3}$

Rewrite the expression.

$y = \frac{3 x}{1} + \frac{12}{- 3}$

Divide $3 x$ by $1$ .

$y = 3 x + \frac{12}{- 3}$

Divide $12$ by $- 3$ .

$y = 3 x - 4$