Write the Fraction in Simplest Form ((2u^-5)^-1)/(6b^3)

$\frac{{(2 u^{- 5})}^{- 1}}{6 b^{3}}$

Move ${(2 u^{- 5})}^{- 1}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{6 b^{3} (2 u^{- 5})}$

Multiply $2$ by $6$ .

$\frac{1}{12 b^{3} u^{- 5}}$

Move $u^{- 5}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{u^{5}}{12 b^{3}}$