Write Using Positive Exponents (3^6)/(3^-4)*3^-1

$\frac{3^{6}}{3^{- 4}} \cdot 3^{- 1}$

Step 1

Move $3^{- 4}$ to the numerator in $\frac{3^{6}}{3^{- 4}}$ using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$3^{6} \cdot 3^{4}$

Step 2

Move $3^{- 1}$ to the denominator in $3^{- 1}$ using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{3}$

Step 3

Rewrite $\frac{3^{6}}{3^{- 4}} \cdot 3^{- 1}$ with positive exponents.

$3^{6} \cdot 3^{4} \cdot \frac{1}{3}$