Determine if True log base 6 of 18- log base 6 of 6 = log base 6 of 3

$\log_{6} (18) - \log_{6} (6) = \log_{6} (3)$

Step 1

Rewrite the equation in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $y = l o g (b) (x)$ is equivalent to $b^{y} = x$ .

$6^{\log_{6} (3)} = 3$

Step 2

The left side $3$ is equal to the right side $3$ , which means that the given statement is always true.

True

Determine if True log base 6 of 18- log base 6 of 6 = log base 6 of 3

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