Evaluate -1/3 cube root of 27

$- \frac{1}{3} \sqrt[3]{27}$

Rewrite $27$ as $3^{3}$ .

$- \frac{1}{3} \cdot \sqrt[3]{3^{3}}$

Pull terms out from under the radical, assuming real numbers.

$- \frac{1}{3} \cdot 3$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{1}{3}$ into the numerator.

$\frac{- 1}{3} \cdot 3$

Cancel the common factor.

$\frac{- 1}{3} \cdot 3$

Rewrite the expression.

$- 1$