Evaluate 1/( cube root of x^4)

$\frac{1}{\sqrt[3]{x^{4}}}$

Step 1

Simplify the denominator.

Factor out $x^{3}$ .

$\frac{1}{\sqrt[3]{x^{3} x}}$

Pull terms out from under the radical.

$\frac{1}{x \sqrt[3]{x}}$

Step 2

Multiply $\frac{1}{x \sqrt[3]{x}}$ by $\frac{{\sqrt[3]{x}}^{2}}{{\sqrt[3]{x}}^{2}}$ .

$\frac{1}{x \sqrt[3]{x}} \cdot \frac{{\sqrt[3]{x}}^{2}}{{\sqrt[3]{x}}^{2}}$

Step 3

Combine and simplify the denominator.

Multiply $\frac{1}{x \sqrt[3]{x}}$ by $\frac{{\sqrt[3]{x}}^{2}}{{\sqrt[3]{x}}^{2}}$ .

$\frac{{\sqrt[3]{x}}^{2}}{x \sqrt[3]{x} {\sqrt[3]{x}}^{2}}$

Move $\sqrt[3]{x}$ .

$\frac{{\sqrt[3]{x}}^{2}}{x (\sqrt[3]{x} {\sqrt[3]{x}}^{2})}$

Raise $\sqrt[3]{x}$ to the power of $1$ .

$\frac{{\sqrt[3]{x}}^{2}}{x ({\sqrt[3]{x}}^{1} {\sqrt[3]{x}}^{2})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{{\sqrt[3]{x}}^{2}}{x {\sqrt[3]{x}}^{1 + 2}}$

Add $1$ and $2$ .

$\frac{{\sqrt[3]{x}}^{2}}{x {\sqrt[3]{x}}^{3}}$

Rewrite ${\sqrt[3]{x}}^{3}$ as $x$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x}$ as $x^{\frac{1}{3}}$ .

$\frac{{\sqrt[3]{x}}^{2}}{x {(x^{\frac{1}{3}})}^{3}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{{\sqrt[3]{x}}^{2}}{x \cdot x^{\frac{1}{3} \cdot 3}}$

Combine $\frac{1}{3}$ and $3$ .

$\frac{{\sqrt[3]{x}}^{2}}{x \cdot x^{\frac{3}{3}}}$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{{\sqrt[3]{x}}^{2}}{x \cdot x^{\frac{3}{3}}}$

Rewrite the expression.

$\frac{{\sqrt[3]{x}}^{2}}{x \cdot x^{1}}$

Simplify.

$\frac{{\sqrt[3]{x}}^{2}}{x \cdot x}$

Step 4

Multiply $x$ by $x$ .

$\frac{{\sqrt[3]{x}}^{2}}{x^{2}}$

Step 5

Rewrite ${\sqrt[3]{x}}^{2}$ as ${(x^{2})}^{\frac{1}{3}}$ .

$\frac{\sqrt[3]{x^{2}}}{x^{2}}$