Evaluate 12+((2^3)÷(2/3))-2

$12 + (2^{3} \div \frac{2}{3}) - 2$

Remove parentheses.

$12 + 2^{3} \div \frac{2}{3} - 2$

Find the common denominator.

Write $12$ as a fraction with denominator $1$ .

$\frac{12}{1} + 2^{3} \div \frac{2}{3} - 2$

Multiply $\frac{12}{1}$ by $\frac{\frac{2}{3}}{\frac{2}{3}}$ .

$\frac{12}{1} \cdot \frac{\frac{2}{3}}{\frac{2}{3}} + 2^{3} \div \frac{2}{3} - 2$

Multiply $\frac{12}{1}$ by $\frac{\frac{2}{3}}{\frac{2}{3}}$ .

$\frac{12 (\frac{2}{3})}{\frac{2}{3}} + 2^{3} \div \frac{2}{3} - 2$

Write $- 2$ as a fraction with denominator $1$ .

$\frac{12 (\frac{2}{3})}{\frac{2}{3}} + 2^{3} \div \frac{2}{3} + \frac{- 2}{1}$

Multiply $\frac{- 2}{1}$ by $\frac{\frac{2}{3}}{\frac{2}{3}}$ .

$\frac{12 (\frac{2}{3})}{\frac{2}{3}} + 2^{3} \div \frac{2}{3} + \frac{- 2}{1} \cdot \frac{\frac{2}{3}}{\frac{2}{3}}$

Multiply $\frac{- 2}{1}$ by $\frac{\frac{2}{3}}{\frac{2}{3}}$ .

$\frac{12 (\frac{2}{3})}{\frac{2}{3}} + 2^{3} \div \frac{2}{3} + \frac{- 2 (\frac{2}{3})}{\frac{2}{3}}$

Combine the numerators over the common denominator.

$\frac{12 (\frac{2}{3}) + 2^{3} - 2 (\frac{2}{3})}{\frac{2}{3}}$

Simplify each term.

Cancel the common factor of $3$ .

Factor $3$ out of $12$ .

$\frac{3 (4) \frac{2}{3} + 2^{3} - 2 (\frac{2}{3})}{\frac{2}{3}}$

Cancel the common factor.

$\frac{3 \cdot 4 \frac{2}{3} + 2^{3} - 2 (\frac{2}{3})}{\frac{2}{3}}$

Rewrite the expression.

$\frac{4 \cdot 2 + 2^{3} - 2 (\frac{2}{3})}{\frac{2}{3}}$

Multiply $4$ by $2$ .

$\frac{8 + 2^{3} - 2 (\frac{2}{3})}{\frac{2}{3}}$

Raise $2$ to the power of $3$ .

$\frac{8 + 8 - 2 (\frac{2}{3})}{\frac{2}{3}}$

Multiply $- 2 (\frac{2}{3})$ .

Combine $- 2$ and $\frac{2}{3}$ .

$\frac{8 + 8 + \frac{- 2 \cdot 2}{3}}{\frac{2}{3}}$

Multiply $- 2$ by $2$ .

$\frac{8 + 8 + \frac{- 4}{3}}{\frac{2}{3}}$

Move the negative in front of the fraction.

$\frac{8 + 8 - \frac{4}{3}}{\frac{2}{3}}$

Find the common denominator.

Write $8$ as a fraction with denominator $1$ .

$\frac{\frac{8}{1} + 8 - \frac{4}{3}}{\frac{2}{3}}$

Multiply $\frac{8}{1}$ by $\frac{3}{3}$ .

$\frac{\frac{8}{1} \cdot \frac{3}{3} + 8 - \frac{4}{3}}{\frac{2}{3}}$

Multiply $\frac{8}{1}$ by $\frac{3}{3}$ .

$\frac{\frac{8 \cdot 3}{3} + 8 - \frac{4}{3}}{\frac{2}{3}}$

Write $8$ as a fraction with denominator $1$ .

$\frac{\frac{8 \cdot 3}{3} + \frac{8}{1} - \frac{4}{3}}{\frac{2}{3}}$

Multiply $\frac{8}{1}$ by $\frac{3}{3}$ .

$\frac{\frac{8 \cdot 3}{3} + \frac{8}{1} \cdot \frac{3}{3} - \frac{4}{3}}{\frac{2}{3}}$

Multiply $\frac{8}{1}$ by $\frac{3}{3}$ .

$\frac{\frac{8 \cdot 3}{3} + \frac{8 \cdot 3}{3} - \frac{4}{3}}{\frac{2}{3}}$

Combine the numerators over the common denominator.

$\frac{\frac{8 \cdot 3 + 8 \cdot 3 - 4}{3}}{\frac{2}{3}}$

Simplify each term.

Multiply $8$ by $3$ .

$\frac{\frac{24 + 8 \cdot 3 - 4}{3}}{\frac{2}{3}}$

Multiply $8$ by $3$ .

$\frac{\frac{24 + 24 - 4}{3}}{\frac{2}{3}}$

Simplify by adding and subtracting.

Add $24$ and $24$ .

$\frac{\frac{48 - 4}{3}}{\frac{2}{3}}$

Subtract $4$ from $48$ .

$\frac{\frac{44}{3}}{\frac{2}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$\frac{44}{3} \cdot \frac{3}{2}$

Cancel the common factor of $2$ .

Factor $2$ out of $44$ .

$\frac{2 (22)}{3} \cdot \frac{3}{2}$

Cancel the common factor.

$\frac{2 \cdot 22}{3} \cdot \frac{3}{2}$

Rewrite the expression.

$\frac{22}{3} \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{22}{3} \cdot 3$

Rewrite the expression.

$22$

Evaluate 12+((2^3)÷(2/3))-2

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