Evaluate (17x^0y^-8)/(4^-2z^-6)

$\frac{17 x^{0} y^{- 8}}{4^{- 2} z^{- 6}}$

Step 1

Simplify.

Move $y^{- 8}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{17}{4^{- 2} z^{- 6} y^{8}}$

Move $4^{- 2}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{17 \cdot 4^{2}}{z^{- 6} y^{8}}$

Move $z^{- 6}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{17 \cdot 4^{2} z^{6}}{y^{8}}$

Step 2

Simplify the numerator.

Raise $4$ to the power of $2$ .

$\frac{17 \cdot 16 z^{6}}{y^{8}}$

Multiply $17$ by $16$ .

$\frac{272 z^{6}}{y^{8}}$