Evaluate (3/4)^3*(-16)^2

${(\frac{3}{4})}^{3} \cdot {(- 16)}^{2}$

Simplify the expression.

Apply the product rule to $\frac{3}{4}$ .

$\frac{3^{3}}{4^{3}} \cdot {(- 16)}^{2}$

Raise $3$ to the power of $3$ .

$\frac{27}{4^{3}} \cdot {(- 16)}^{2}$

Raise $4$ to the power of $3$ .

$\frac{27}{64} \cdot {(- 16)}^{2}$

Raise $- 16$ to the power of $2$ .

$\frac{27}{64} \cdot 256$

$\frac{27}{64} \cdot 256$

Cancel the common factor of $64$ .

Factor $64$ out of $256$ .

$\frac{27}{64} \cdot (64 (4))$

Cancel the common factor.

$\frac{27}{64} \cdot (64 \cdot 4)$

Rewrite the expression.

$27 \cdot 4$

$27 \cdot 4$

Multiply $27$ by $4$ .

$108$

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