Evaluate Using the Given Value f(-3)=8(2)^-3

$f (- 3) = 8 {(2)}^{- 3}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f (- 3) = 8 (\frac{1}{2^{3}})$

Step 2

Raise $2$ to the power of $3$ .

$f (- 3) = 8 (\frac{1}{8})$

Step 3

Cancel the common factor of $8$ .

Cancel the common factor.

$f (- 3) = 8 (\frac{1}{8})$

Rewrite the expression.

$f (- 3) = 1$