Evaluate 3 natural log of e^4+ natural log of e^-17

$3 \ln (e^{4}) + \ln (e^{- 17})$

Simplify each term.

Use logarithm rules to move $4$ out of the exponent.

$3 (4 \ln (e)) + \ln (e^{- 17})$

The natural logarithm of $e$ is $1$ .

$3 (4 \cdot 1) + \ln (e^{- 17})$

Multiply $4$ by $1$ .

$3 \cdot 4 + \ln (e^{- 17})$

Multiply $3$ by $4$ .

$12 + \ln (e^{- 17})$

Use logarithm rules to move $- 17$ out of the exponent.

$12 - 17 \ln (e)$

The natural logarithm of $e$ is $1$ .

$12 - 17 \cdot 1$

Multiply $- 17$ by $1$ .

$12 - 17$

Subtract $17$ from $12$ .

$- 5$