Evaluate 3 square root of 16-5

$3 \sqrt{16} - 5$

Simplify each term.

Rewrite $16$ as $4^{2}$ .

$3 \sqrt{4^{2}} - 5$

Pull terms out from under the radical, assuming positive real numbers.

$3 \cdot 4 - 5$

Multiply $3$ by $4$ .

$12 - 5$

Subtract $5$ from $12$ .

$7$