Evaluate 5-(6^2)÷4-3

$5 - 6^{2} \div 4 - 3$

Find the common denominator.

Write $5$ as a fraction with denominator $1$ .

$\frac{5}{1} - 6^{2} \div 4 - 3$

Multiply $\frac{5}{1}$ by $\frac{4}{4}$ .

$\frac{5}{1} \cdot \frac{4}{4} - 6^{2} \div 4 - 3$

Multiply $\frac{5}{1}$ by $\frac{4}{4}$ .

$\frac{5 \cdot 4}{4} - 6^{2} \div 4 - 3$

Write $- 3$ as a fraction with denominator $1$ .

$\frac{5 \cdot 4}{4} - 6^{2} \div 4 + \frac{- 3}{1}$

Multiply $\frac{- 3}{1}$ by $\frac{4}{4}$ .

$\frac{5 \cdot 4}{4} - 6^{2} \div 4 + \frac{- 3}{1} \cdot \frac{4}{4}$

Multiply $\frac{- 3}{1}$ by $\frac{4}{4}$ .

$\frac{5 \cdot 4}{4} - 6^{2} \div 4 + \frac{- 3 \cdot 4}{4}$

Combine the numerators over the common denominator.

$\frac{5 \cdot 4 - 6^{2} - 3 \cdot 4}{4}$

Simplify each term.

Multiply $5$ by $4$ .

$\frac{20 - 6^{2} - 3 \cdot 4}{4}$

Raise $6$ to the power of $2$ .

$\frac{20 - 1 \cdot 36 - 3 \cdot 4}{4}$

Multiply $- 1$ by $36$ .

$\frac{20 - 36 - 3 \cdot 4}{4}$

Multiply $- 3$ by $4$ .

$\frac{20 - 36 - 12}{4}$

Simplify the expression.

Subtract $36$ from $20$ .

$\frac{- 16 - 12}{4}$

Subtract $12$ from $- 16$ .

$\frac{- 28}{4}$

Divide $- 28$ by $4$ .

$- 7$